-4m^2+2m-11=-5m^2

Solution for -4m^2+2m-11=-5m^2 equation:

-4m^2+2m-11=-5m^2

We move all terms to the left:

-4m^2+2m-11-(-5m^2)=0

We get rid of parentheses

-4m^2+5m^2+2m-11=0

We add all the numbers together, and all the variables

m^2+2m-11=0

a = 1; b = 2; c = -11;
Δ = b2-4ac
Δ = 22-4·1·(-11)
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4\sqrt{3}}{2*1}=\frac{-2-4\sqrt{3}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4\sqrt{3}}{2*1}=\frac{-2+4\sqrt{3}}{2}
$